H=-4.9x^2-2x+22

Solution for H=-4.9x^2-2x+22 equation:

=-4.9H^2-2H+22

We move all terms to the left:

-(-4.9H^2-2H+22)=0

We get rid of parentheses

4.9H^2+2H-22=0

a = 4.9; b = 2; c = -22;
Δ = b2-4ac
Δ = 22-4·4.9·(-22)
Δ = 435.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{435.2}}{2*4.9}=\frac{-2-\sqrt{435.2}}{9.8}
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{435.2}}{2*4.9}=\frac{-2+\sqrt{435.2}}{9.8}
$